Class 9 SEBA Theorem 8.1 | Diagonals of a Parallelogram Divide It into Two Congruent Triangles
Автор: Ali's Coahing
Загружено: 2025-10-10
Просмотров: 90
In this video, we explain Class 9 SEBA Theorem 8.1 –
👉 “Diagonals of a parallelogram divide it into two congruent triangles.”
You’ll learn:
📘 Step-by-step proof with clear explanation
📐 Concept of congruent triangles
📏 How diagonals of a parallelogram form equal triangles
📊 Easy method to remember for exams
Perfect for Class 9 SEBA Maths students preparing for exams or revising Geometry Chapter 8.
Watch till the end to master the theorem easily!
📞 For study materials or guidance, contact on WhatsApp: 7035221285
#Class9SEBAMaths #SEBAtheorem #Geometry #Theorem8point1 #Parallelogram #CongruentTriangles
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