i-th root of -1

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We know the principal square root of -1 is the imaginary unit i but what if we have the i-th root of -1? We will do a quick review on converting a complex number from the standard form a+bi to its polar form re^(i*theta). Then we will see the surprising answer that the i-th root of -1 will actually give us.

Related videos:
the proof of the Euler's identity (with the Taylor series):    • Euler’s identity proof for calculus 2 stud...  

i-th root of i:    • i-th root of i  

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0:00 what's the i-th root of -1
5:30 check out Brilliant
6:08 challenging question (-1)^pi
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