Q) Let 𝜋/2𝑥𝜋 be such that cot𝑥=(−5)/√11. Then (sin 11𝑥/2)(sin6𝑥−cos6𝑥)+(cos 11𝑥/2)(sin6𝑥+cos6𝑥) is

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Q) Let 𝜋/2𝑥𝜋 be such that cot𝑥=(−5)/√11. Then
(sin 11𝑥/2)(sin6𝑥−cos6𝑥)+(cos 11𝑥/2)(sin6𝑥+cos6𝑥)
is equal to:
(A) (√11−1)/(2√3)(B) (√11+1)/(2√3)(C) (√11+1)/(3√2)(D) (√11−1)/(3√2)

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Q) If 2sin^3 𝑥+sin2𝑥cos𝑥+4sin𝑥−4=0 has exactly
3 solutions in the interval [0,n𝜋/2],n∈N, then the roots
of the equation 𝑥^2+𝑛𝑥+(𝑛−3)=0 belong to :
(1) (0,∞)(2) (−∞,0)(3) (−√17/2,√17/2)(4) Z