Isolated Footing Bar Bending Schedule | BBS Calculation Step by Step
Автор: Simplified Academy
Загружено: 2026-01-20
Просмотров: 117
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Video Description : ✅Bar Bending Schedule for Isolated Footing
📌Given data
Size Of Footing = 2000 mm ⨯ 1500 mm
Clear Cover = 50 mm
Main Bar = 12 mm@100 mmc/c
Hook Length = 9d
📌Cutting Length Of Main Bar
= Width Of Footing – ( 2 ⨯ Clear Cover )
( 2 ⨯ 9 d Hook ) – ( 2 BEND 90° )
= 1500 – (2⨯50) + (2⨯9⨯12 ) – (2 ⨯2 ⨯ 12)
= 1500 – 100 + 216 – 48
= 1568mm
📌Cutting Length Of Distribution Bar
= Length Of Footing – ( 2 ⨯ Clear Cover ) + ( 2 ⨯ 9 d Hook ) – ( 2 BEND 90° )
= 2000 – (2⨯50) + (2⨯9⨯10 ) – (2⨯2⨯10)
= 2000 – 100 + 180 – 40
= 2040mm
📌Number Of Main Bar (12mm) in Footing
= Number of Main =Length − (2⨯Clear Cover) / 2 + 1
= 2000 − (2 ⨯50 )/100 + 1
= 1900/100 + 1
= 20.Nos
📌Number Of Distribution Bar(10mm) Footing
= Number Of Dis. Bar = Width − (2⨯Clear Cover) /Spacing + 1
=1400/150 + 1
=10.33 Nos.
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Video Tags : #IsolatedFooting
#BarBendingSchedule
#BBSCalculation
#CivilEngineering
#FootingReinforcement
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