Two Best Non Overlapping Events | Leetcode 2054 | Binary Search + Suffix Max | C++ Hindi

LeetCode Problem of the Day (POTD) - 23 Dec 2025
Problem 2054: Two Best Non-Overlapping Events

In this video, we solve LeetCode 2054 using an efficient O(n log n) approach.
Binary Search (lower_bound) and Suffix Maximum Precomputation.

Problem link:
https://leetcode.com/problems/two-bes...

Approach:
1) Sort events by start time
2) Build a suffix best array where best[i] stores the maximum event value from i to end
3) For each event, use binary search to find the next valid event
whose start time is at least end time plus one
4) Take maximum of:
choosing only one event
choosing two non-overlapping events

Complexity:
Time complexity: O(n log n)
Space complexity: O(n)

Language: C++

If you are preparing for coding interviews or LeetCode daily challenges,
this pattern using binary search and suffix best is very useful.


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