ADDITION AND SUBSTRACION OF PHASORS EXAMPLE 2- AC CIRCUITS

This video provides a step-by-step walkthrough of a more complex phasor addition and subtraction problem in AC circuit analysis. It demonstrates how to handle currents with different frequencies and phase angles at a circuit node. The tutorial focuses on resolving phasors into their X and Y components to find the resultant current, a crucial technique when the phasors are not 90 degrees apart.



00:00:00 - Introduction to the Problem (Node with Multiple Currents)
00:00:55 - Key Principle: Adding Phasors with the Same Frequency
00:01:53 - Identifying Currents by Frequency (ωt and 3ωt)
00:03:02 - Setting up the Problem for ωt Frequency Components
00:04:33 - Resolving Phasors into X and Y Components
00:08:06 - Calculating the X Component
00:09:07 - Calculating the Y Component
00:12:08 - Finding the Resultant Magnitude for ωt Components
00:13:54 - Finding the Phase Angle for ωt Components
00:16:48 - Writing the Final Expression for the ωt Component of I4
00:18:40 - Repeating the Process for the 3ωt Frequency Components
00:25:07 - Finding the Resultant Magnitude for 3ωt Components
00:26:24 - Finding the Phase Angle for 3ωt Components
00:28:21 - Writing the Final Expression for the 3ωt Component of I4
00:29:50 - Final Result: The Complete Expression for Current I4

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