Super Node Analysis, Lecture-01, Electrical circuit. Nodal analysis.

Today, we will try to answer the common question of why we use Supernode circuit analysis while we can simplify the circuit by simple Node or Nodal Circuit analysis.
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In the previous article, we have discussed why we use supermesh circuit analysis instead of using simple mesh analysis for circuit simplification. If you got this point, then this is the same case about the discussion.
We’ve already discussed how we can take the help of Kirchhoff's Current Law (KCL) to determine the direction and magnitude of the current flowing in and out of the nodes, and through the branches of any given network. In most Step 1) Reviewing the network, we can see that we are given two resistors and two current sources, along with their values. But there’s also a voltage source of 2V present between the nodes N1 and N2. We’ll assume that the voltages at the nodes N1 and N2 are V1 and V2 respectively. cases, we can easily apply the nodal analysis to figure out the required information. But there are some exceptions when the straightforward method just doesn’t work.
Step 1) Reviewing the network, we can see that we are given two resistors and two current sources, along with their values. But there’s also a voltage source of 2V present between the nodes N1 and N2. We’ll assume that the voltages at the nodes N1 and N2 are V1 and V2 respectively.
Step 2) Here we already have our reference node at the bottom of the network. So this step will not bother us at all.

Step 3) Let’s try to write down the branch current equations for the three currents I1, I2, and I3
Step 4) Applying nodal analysis at node N1 and putting in the expressions we obtained in the previous step,
Step 5) We finally have two unknowns and also two equations. Now we just need to do some basic math and we can get the values of V1 and V2. Once we’ve got those values, we can plug them into our branch current equations and get the values of the unknown currents as well. But this is a pretty long process for obtaining the values of branch current. We can take a much more generalized and shorter approach to obtain the same result in much less time.