Reverse Integer in Java | Clean & Easy LeetCode Solution Explained | Real Software engineer POV
Автор: Ngane Emmanuel
Загружено: 2025-10-17
Просмотров: 54
Master the *Reverse Integer* problem in Java (LeetCode #7)!
In this video, I walk through how to reverse an integer — digit by digit — while safely handling *integer overflow* (2³¹ − 1 and −2³¹).
We’ll break it down step-by-step to make it easy to follow for both beginners and those preparing for coding interviews.
💻 *Code Explained:*
Extracting digits using modulus `%`
Building the reversed number
Detecting overflow before it happens
Returning the correct result safely
🔥 *Topics Covered:*
Java basics (loops, conditionals, operators)
Integer limits and overflow
Clean and efficient logic
📚 *More Java Problems Solved:*
👉 Median of Two Sorted Arrays
👉 String to Integer (MyAtoi)
👉 Longest Common Prefix
💬 *Connect with me:*
🔗 LinkedIn: [Ngane Emmanuel](linkedin.com/in/ngane-emmanuel-b25242150/)
🐦 Twitter: [@NganeEmmanuel](twitter.com/NganeEmmanuel)
#Java #LeetCode #CodingInterview #ReverseInteger #NganeEmmanuel
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🏷️ *Tags*
leetcode, reverse integer, java coding, java programming, coding interview, java interview, data structures, algorithms, reverse number, integer overflow, reverse digits, leetcode 7, java leetcode solution, ngane emmanuel, coding problems, programming tutorials, java logic, beginner java projects
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