Class 11 Physics NCERT Example 2.1 The position of an object moving along x-axis is given by x=a+bt2

In this video, we have solved Example 2.1 from Class 11 NCERT Physics Chapter 2: Motion in a Straight Line. This example helps you understand how to find instantaneous velocity and average velocity using the position-time equation.

0:01 The position of an object
moving along x-axis is given by x = a + bt2
where a = 8.5 m, b = 2.5 m s–2 and t is
measured in seconds. What is its velocity at
t = 0 s and t = 2.0 s. What is the average
velocity between t = 2.0 s and t = 4.0 s ?

🧠 What you’ll learn:
• How to differentiate a position-time equation to get velocity
• How to calculate velocity at a given instant (t = 0 s and t = 2.0 s)
• How to find average velocity between two time intervals (t = 2.0 s to t = 4.0 s)
• Concept of kinematics and motion in one dimension

🧑‍🎓 This video is perfect for:
• Class 11 CBSE students
• NEET and JEE aspirants revising kinematics
• Anyone who wants to build strong conceptual clarity in physics

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