nth derivative e^ax .cos(bx+c)|| Successive Differentiation e^ax .cos(bx+c)

Автор: Let's Unlock Maths

Загружено: 2023-07-30

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Here we have differentiate e^ax.cos(bx+c) successively to find nth derivative.

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nth derivative e^ax .cos(bx+c)|| Successive Differentiation e^ax .cos(bx+c)

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