LeetCode 1025 Divisor Game in Python | Easy Coding Tutorial for Beginners
Автор: JR: Educational Channel
Загружено: 2025-05-17
Просмотров: 213
Solve LeetCode 1025 "Divisor Game" in Python with this beginner-friendly coding tutorial! In this problem, Alice and Bob take turns subtracting divisors from a number `n`, starting with Alice, and the player who cannot make a move loses (e.g., n = 2 returns true because Alice wins). We’ll discover a simple pattern: Alice wins if `n` is even, and loses if `n` is odd. We’ll also explore a dynamic programming approach to confirm this pattern. Perfect for Python learners, coding beginners, or anyone prepping for coding interviews!
🔍 *What You'll Learn:*
Understanding LeetCode 1025’s game rules
Identifying the winning pattern for Alice (n % 2 == 0)
Exploring a dynamic programming solution to understand the game
Testing with example cases
💻 *Code Used in This Video:*
class Solution(object):
def divisorGame(self, n):
"""
:type n: int
:rtype: bool
"""
return n % 2 == 0
Test cases
solution = Solution()
Test case 1: n = 2 (Alice wins)
print(solution.divisorGame(2)) # Output: True
Alice chooses 1 (divisor of 2), 2-1=1, Bob can't move, Alice wins
Test case 2: n = 3 (Alice loses)
print(solution.divisorGame(3)) # Output: False
Alice chooses 1 (divisor of 3), 3-1=2, Bob chooses 1, 2-1=1, Alice can't move, Bob wins
Test case 3: n = 1 (Alice loses)
print(solution.divisorGame(1)) # Output: False
No divisors less than 1, Alice can't move, Bob wins
Test case 4: n = 4 (Alice wins)
print(solution.divisorGame(4)) # Output: True
Alice chooses 1, 4-1=3, Bob chooses 1, 3-1=2, Alice chooses 1, 2-1=1, Bob can't move
Alternative: Dynamic Programming solution (to understand the pattern)
class SolutionDP(object):
def divisorGame(self, n):
"""
:type n: int
:rtype: bool
"""
dp[i] represents whether Alice can win starting with number i
dp = [False] * (n + 1)
for i in range(1, n + 1):
for x in range(1, i):
if i % x == 0 and not dp[i - x]:
dp[i] = True
break
return dp[n]
solution_dp = SolutionDP()
print("\nDP solution:")
print(solution_dp.divisorGame(2)) # Output: True
print(solution_dp.divisorGame(3)) # Output: False
🌟 *Why Solve LeetCode 1025?*
This problem is a great introduction to game theory and pattern recognition in Python, a common topic in coding interviews! The simple solution `n % 2 == 0` has O(1) time complexity, while the dynamic programming approach (O(n * sqrt(n))) helps us understand why the pattern holds: Alice can always force a win if `n` is even by making optimal moves. Master this, and you’ll be ready for more advanced LeetCode challenges!
📚 *Who’s This For?*
Python beginners learning coding
Coding enthusiasts tackling LeetCode problems
Developers prepping for technical interviews
👍 Like, subscribe, and comment: What LeetCode problem should we solve next? Next up: More LeetCode game theory problems—stay tuned!
#LeetCodeTutorial #DivisorGame #PythonCoding #LearnCoding #InterviewPrep
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