Proof: Limit of sinx/x as x approaches 0 with Squeeze Theorem | Calculus 1
Автор: Wrath of Math
Загружено: 2023-06-13
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We prove the limit of sinx/x as x goes to 0 equals 1 using the squeeze theorem and a geometric argument involving sectors and triangles on the unit circle. #calculus1 #apcalculus
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Squeeze Theorem Explained: (coming soon)
Limit of (1-cosx)/x: • Limit of (1-cos(x))/x as x approaches 0 | ...
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