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Proof by contradiction: axᵏ + b/xᵏ ≥ 2√ab for positive x, a, b
Автор: Dr Ben Yelverton
Загружено: 2021-03-26
Просмотров: 144
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How to prove by contradiction that axᵏ + b/xᵏ ≥ 2√ab, for positive x, a & b, and real k. The thumbnail shows the graphs of y = axᵏ + b/xᵏ for fixed a & b, and various values of k.
About me: I studied Physics at the University of Cambridge, then stayed on to get a PhD in Astronomy. During my PhD, I also spent four years teaching Physics undergraduates at the university. Now, I'm working as a private tutor, teaching Physics & Maths up to A Level standard.
My website: https://benyelverton.com/
#proof #contradiction #proofbycontradiction #curves #graphs #minimum #minima #lowerbound #realnumbers #inequalities #mathematics #maths #math #education #alevel
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