15. Find Element with Maximum Frequency in an Array | Brute Force vs Optimized | DSA in Hindi
Автор: Piyush Builds
Загружено: 2025-12-30
Просмотров: 20
In this video, we solve a very common DSA interview question:
👉 Find the element with maximum frequency in an array
We cover both approaches so beginners can clearly understand the difference:
🔹 Approach 1: Brute Force (Naive)
Compare each element with every other element
Count frequency manually
Easy to understand but slow for large arrays
Time Complexity: O(n²)
Space Complexity: O(1)
🔹 Approach 2: Optimized using HashMap
Store frequency of elements in a HashMap
Find the element with the highest count
Best approach for interviews
Time Complexity: O(n)
Space Complexity: O(n)
💻 What You’ll Learn
✔ How frequency counting works
✔ Why brute force is inefficient
✔ How HashMap optimizes performance
✔ Interview-friendly solution explanation
✔ Java implementation with clear logic
🧪 Example Used
Input:
[1, 3, 2, 1, 4, 1, 3, 3, 3]
Output:
3 (appears maximum times)
🎯 Interview Tip
This question is frequently asked in Amazon, Microsoft, Flipkart, Infosys interviews.
Always explain both approaches, but implement the optimized one.
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