Lagrange Multipliers #2: Two Variables, 1 Constraint

Автор: turksvids

Загружено: 2020-02-23

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In this video we go over how to use Lagrange Multipliers to find the absolute maximum and absolute minimum of a function given a constraint curve. Specifically we find the maximum and minimum values of f(x,y) = 4x^3+y^2 given 2x^2+y^2=1. If you're neat and organized you'll be fine!

Some other things you might hear while you do these: constrained optimization, absolute max/min over a curve.

This is a very common topic to cover in a Calculus III/Multivariable calculus course. Good luck!

Lagrange Multipliers #2: Two Variables, 1 Constraint

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