Could a Giant Ice Cube Cool the Earth? - Nuclear Engineer Reacts to Zack D. Films

Simplified Calculations:
Volume: 23 miles per side = 37 km per side^3 = 50,653 km^3 = 5.0653 e13 m^3
Density: 917 kg/m^3
Mass: 917 kg/m^3 * 5.0653 e13 m^3 = 4.65 e15 kg

Latent heat of fusion to melt ice: 334,000 J/kg
Heat to melt ice: 4.65 e15 kg * 334,000 J/kg =1.55 e22 J
Specific heat of water: 4186 J/kgK
Heat to raise melted ice from 0 C to 15 C (avg. ocean temp.): 4.65 e15 kg * 15 K * 4186 J/kgK = 2.92 e21 J.
Total Heat = 1.55 e22 J + 2.92 e21 J = 1.84 e22 J

Mass of oceans = 1.4 e21 kg
To raise oceans 1 degree = 1.4 e21 kg * 4186 J/kgK = 5.86 e24 J
The ice cube heats the ocean by 1.84 e22 J/5.86 e24 J =0.003 C

Sea level rise:
Surface area of oceans: 3.61 e8 km^2 = 3.61 e14 m^2
Displaced volume of cube = 5.0653 e13 m^3
Rise = 5.0653 e13 m^3/3.61 e14 m^2 = 0.14 m = 14cm

Original Video ‪@zackdfilms‬    • Could A Giant Ice Cube Cool The Earth? 🤔