R/M is a Feild if and only M is a Maximal Ideal || Theorem || Ring Theory
Автор: Uneeb Awais
Загружено: 2021-09-14
Просмотров: 16243
In this video, we prove the famous theorem in Ring Theory:
👉 R/M is a field if and only if M is a maximal ideal.
This is a fundamental result in Abstract Algebra and is very important for competitive and university-level exams. The proof is explained step by step to make it clear and easy for students preparing for:
CSIR NET / JRF Mathematics
IIT JAM Mathematics
GATE Mathematics
TIFR & NBHM Entrance Exams
MSc & PhD Entrance Tests (India & Pakistan)
This theorem connects the concept of maximal ideals with fields, making it a key result in higher algebra.
If you are studying Ring Theory, Abstract Algebra, or Group Theory, this lecture will strengthen your understanding and exam preparation.
🔔 Subscribe for more proofs, theorems, and solved problems in Abstract Algebra & Ring Theory.
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![R is a Field iff Polynomial Ring R[x] is Principal Ideal Domain - Proof- ED - Lesson 20](https://ricktube.ru/thumbnail/SaEU6_m8NYg/mqdefault.jpg)
