Class 11th Physics Chapter 2 Example 1, 2 and 3 | NCERT Solutions | Motion in Straight line
Автор: Physics ke Concepts
Загружено: 2026-01-02
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In this video Exercise Example 1, 2 and 3 of chapter 2 (Motion in Straight line) is explained in detail.
Playlist link : • NCERT Examples and Exercise Question
Example 2.1
The position of an object moving along x-axis is given by x = a + bt2
where a = 8.5 m, b = 2.5 m s–2 and t is measured in seconds. What is its velocity at t = 0 s and t = 2.0 s. What is the average velocity between t = 2.0 s and t = 4.0 s ?
Example 2.2 Obtain equations of motion for constant acceleration using method of calculus.
Example 2.3 A ball is thrown vertically upwards with a velocity of 20 m s–1 from the top of a multistorey building. The height of the point from where the ball is thrown is 25.0 m from the ground. (a) How high will the ball rise ? and (b) how long will it be before the ball hits the ground? Take g = 10 m s–2.
This series is helpful for students who stuck in concepts and problems of NCERT book and also helpful for students who just started their IIT JEE or NEET preparation.
Thank You for Watching
All the best
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