PDA for L = a^n b^n | Pushdown Automata for a^n b^n | Automata Theory | TOC
Автор: TopGATE
Загружено: 2023-03-30
Просмотров: 3748
We can design a pushdown automaton (PDA) to recognize the language L = (a^n b^n / n is greater than or equal to 1) as follows:
The PDA will have a single stack symbol Z0 at the bottom of the stack, which represents the start of the stack.
For each input symbol a, the PDA will push an 'a' onto the stack.
For each input symbol b, the PDA will pop an 'b' from the stack.
If the PDA reads the end-of-string marker and the stack contains only the symbol Z0, then the input string is accepted.
Introduction to PDA: • Introduction to PDA | Pushdown Automata De...
pda in english
pushdown automata in english
automata lectures in english
toc lectures in english
atfl lectures in english
pda for language
pda for anbn
pda for an bn
pda for a^n b^n
pda
pda example
cse gate
gate exam
pushdown automata
pushdown automata example
topgate
construction of pda
design a pda
top gate questions
cse gate examples
accept a string by pda
automata
gate computer science
computer science lectures
automata for gate
theory of computation
toc
atfl
tafl
automata theory & formal languages
gate lectures
automata lectures
automata theory
toc lectures
toc for gate
theory of computation lectures
Доступные форматы для скачивания:
Скачать видео mp4
-
Информация по загрузке:
