A local high school sells 452 tickets for a basketball game. Student tickets cost 0.75 each and non…

A local high school sells 452 tickets for a basketball game. Student tickets cost 0.75 each and non-student tickets cost 2.00 each. If a total of 492 was raised from the sale of the tickets, how many of each ticket were sold? Let X be the number of student tickets sold and Y be the number of non-student tickets sold. We can set up the following equations: X + Y = 452 (equation 1) 0.75X + 2Y = 492 (equation 2) Solving equation 1 for X, we get: X = 452 - Y Substituting this into equation 2, we have: 0.75(452 - Y) + 2Y = 492 339 - 0.75Y + 2Y = 492 339 + 1.25Y = 492 1.25Y = 492 - 339 1.25Y = 153 Y = 153 / 1.25 Y = 122.4 Since we cannot have a fraction of a ticket, we round Y to the nearest whole number: Y = 122 Substituting this value back into equation 1, we can solve for X: X + 122 = 452 X = 452 - 122 X = 330 Therefore, 330 student tickets and 122 non-student tickets were sold.

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