Find Minimum Time to Reach Last Room I & II || Dijkstra's Algorithm || Leetcode Weekly Contest 422

In this video, I provide a detailed walkthrough of solving LeetCode Weekly Contest 422 problems: "Find Minimum Time to Reach Last Room I" and its advanced version, "Find Minimum Time to Reach Last Room II." Using Dijkstra's algorithm, I demonstrate an efficient approach to handle these grid-based pathfinding problems.

What's Covered:

Explanation of the problem statement and constraints
Step-by-step coding solution using Dijkstra's algorithm
Analysis of edge cases and performance optimization
Tips on navigating similar grid and graph problems in coding interviews
Whether you're prepping for competitive programming or job interviews, understanding how to apply Dijkstra's algorithm effectively is crucial. Tune in to grasp the logic and techniques that can help you solve these and similar medium-level problems on LeetCode.

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3341 . Find Minimum Time to reach last room I II

There is a dungeon with n x m rooms arranged as a grid.

You are given a 2D array moveTime of size n x m, where moveTime[i][j] represents the minimum time in seconds when you can start moving to that room. You start from the room (0, 0) at time t = 0 and can move to an adjacent room. Moving between adjacent rooms takes exactly one second.

Return the minimum time to reach the room (n - 1, m - 1).

Two rooms are adjacent if they share a common wall, either horizontally or vertically.



Example 1:

Input: moveTime = [[0,4],[4,4]]

Output: 6

Explanation:

The minimum time required is 6 seconds.

At time t == 4, move from room (0, 0) to room (1, 0) in one second.
At time t == 5, move from room (1, 0) to room (1, 1) in one second.


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