Empirical Formula Made Easy: % → EF (with TI-84 Chemistry Solver)

Solve empirical formulas step-by-step using percent composition—then check your work with my TI-84 Chemistry Solver program. We cover 5 problems, common rounding traps (1.5, 1.33/1.67, 1.25/1.75), and a simple fix so your calculator gives whole-number subscripts every time.

🔗 Links mentioned
• Chemistry Solver Bundle (TI-84 Plus CE): https://mcstutoring.com/products/prod...
• Start Here with TI-84 Programs: https://mcstutoring.com/blogs/general...
• Free TI-84 Starter Bundle: https://mcstutoring.com/blogs/general...
What you’ll learn
• Convert % → grams → moles and normalize by the smallest
• Spot fractional ratios (½, ⅓/⅔, ¼/¾…) and scale to whole numbers
• Jump from empirical to molecular formula when molar mass is given
• TI-84 trick: multiplier search (K) to prevent rounding too soon

Chapters
00:00 Intro & method overview
00:40 Setup: % → grams → moles
01:20 #1: Au & O (EF)
02:20 #2a: H & O (EF)
04:05 #3: Cr & O (EF)
04:55 #4: C, H, O (EF)
05:50 #5a: Ag, N, O (EF)
08:40 Wrap-up + practice tips

Quick EF/MF cheat-sheet
Assume 100 g; grams = percents
Moles = grams / atomic mass
Divide all by the smallest moles
If any ratio ≈ .50, .33/.67, .25/.75, etc., multiply all ratios by 2–4 (or up to 8)
Round to integers → Empirical Formula
Molecular Formula: n = (molar mass)/(EF mass); multiply EF subscripts by n

If this helped, please like 👍, subscribe, and drop a problem below—I answer during the school year.
#hashtags
#Chemistry #EmpiricalFormula #MolecularFormula #Stoichiometry #TI84 #TI84PlusCE #ChemistryHomework