Check if Array Is Sorted and Rotated | 3 Approaches | Leetcode 1752 | codestorywithMIK

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Hi Everyone, this is the 65th video of our Playlist "Leetcode Easy".
Now we will be solving an easy practice problem on Array - Check if Array Is Sorted and Rotated | 3 Approaches | Leetcode 1752 | codestorywithMIK
We will solve it from Super Brute Force to Better Brute Force to Most Optimal Solution


Problem Name : Check if Array Is Sorted and Rotated | 3 Approaches | Leetcode 1752 | codestorywithMIK
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Video Summary :
🔹 Approach-1 (Super Brute Force)
We simulate all possible rotations of the array and check if any of them are sorted.

Shift elements and verify if the order remains sorted.
Inefficient due to repeatedly checking all rotations.
🔹 Approach-2 (Better Brute Force)
We sort the original array and check if any rotation matches the sorted array.

Iterate through all rotations and compare with the sorted array.
Avoids unnecessary sorting but still checks multiple possibilities.
🔹 Approach-3 (Optimal)
Count the number of times elements are out of order.

If this count is at most 1, the array can be a rotated sorted array.
Efficient as it avoids unnecessary rotations.

✨ Timelines ✨
00:00 - Introduction
00:16 - Motivation
00:38 - Problem Explanation
03:59 - Approach-1 (Super Brute Force)
14:39 - Approach-2 (Better Brute Force)
21:36 - Approach-3 (Optimal)
28:45 - Coding it up


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